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## A train is travelling at a speed of 90 km h-1. Brakes are applied so as to produce a uniform acceleration of -0.5 m s-2. Find how far the train will go before it is brought to rest.- Physics Cbse class 11

Asked On2017-07-24 06:07:15 by:milan-ransingh

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Download question setAnswersInitial speed of the train, u = 90 km/h = 25 m/s

Final speed of the train, v = 0 (finally the train comes to rest)

Acceleration = -0.5 m s

^{-2}According to third equation of motion:

v

^{ 2}= u^{ 2}+ 2asConcept Note- Wisely choose the equation of motion out of the three, to minimize the calculations.(0)

^{2}= (25)^{2}+ 2 (-0.5) swhere, s is the distance covered by the train

The train will cover a distance of 625 m before it comes to rest.

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