Vapour pressure of water at 20C is 175 mm Hg Calculate the vapour pressure of water at 20C when 15 g of glucose Molar mass 180 g mol 1 is dissolved in 150 g of water CBSE Class12 Chemistry 2015

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Vapour pressure of water at 20ºC is 17.5 mm Hg. Calculate the vapour pressure of water at 20ºC when 15 g of glucose (Molar mass = 180 g mol –1 ) is dissolved in 150 g of water. CBSE- Class12- Chemistry 2015

CBSE- Class12- Chemistry 2015


By:Fututron

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Raoult's Law
 It tells us that in an ideal solution, the vapour pressure of a component is proportional to the mole fraction of that component in solution.
Mole fraction of sucrose=Moles of sucrose/Moles of sucrose + moles of water
Xsucrose= ((200*g)/(342.13*g*mol^-1))/((200*g)/(342.13*g*mol^-1)+(112.3*g)/(18.01*g*mol^-1))=0.0857
Mole fraction of water:
Xwater=((112.3*g)/(18.01*g*mol^-1))/((200*g)/(342.13*g*mol^-1)+(112.3*g)/(18.01*g*mol^-1))=0.914
Note that by definition, χsucrose+χwater=1
Because sucrose is involatile, the vapour pressure of the solution is proportional to the mole fraction of water:
Psolution=χwater×17.5⋅mm⋅Hg
=0.914×17.5⋅mm⋅Hg=16⋅mm⋅Hg


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