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Physics-CBSE-class-10-->View question

## 2009 CBSE Physic class 10

##### An electrician puts a fuse of rating 5A in that part of domestic electrical circuit in which an electrical heater of rating 1.5kW, 220V is operating. What is likely to happen in this case and why? What change, if any, needs to be made?

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Power of the generator, P = 1.5 kW = 1500 Watts

Operating Voltage,        V = 220 V

P = VI

therefore,

The heater will generate a current I = P/V = 1500/220 = 6.8 Amperes.

Now the fuse put in the heater is of 5A. That is, if a current of magnitude greater than 5A passes through it, it will melt. Thus in the given heater where 6.8 A current is being generated, the fuse will melt - breaking the circuit even in the normal working of the heater. Thus, the heater will not function.

Change: Put a fuse of rating greater that 6.8 A.

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