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## The worst case running time to search for an element in a balanced binary search tree with n2 n elements is -gate-computer science-2012

Asked On2017-07-03 11:35:18 by:Amogh

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Download question setAnswers(C) Θ(n)Explanation: Time taken to search an element is Θ(h) where h is the height of Binary Search Tree (BST). The growth of height of a balanced BST is logerthimic in terms of number of nodes. So the worst case time to search an element would be Θ(Log(n*2^n)) which is Θ(Log(n) + Log(2^n)) Which is Θ(Log(n) + n) which can be written as Θ(n).

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