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Physics-CBSE-class-10-->View question

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v = 50 cm
since a same sized, real and inverted image is formed, therefore the object must be placed at the centre of curvature i.e., at 2F1
and since the image is formed at 2F2, hence the distance b/w 2F1 and O is 50 cm.
Thus the needle is placed 50 cm in front of the lens.
R = 50 cm
f = 50/2 = 25 cm
f = 0.25 m
P = 1/f
P = 1/0.25
P = 100/25
P = 4 D
Hence the power of the lens is 4D.

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