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CS6202-Programming-and-Data-Structures-Anna-university-notes-->View question

C data types

What are unit_8,unit_16 in C language? 
I heard that they are data types. As far as I know... There are no such datatypes. Please explain. 
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Answers
We're going to use a variable called testValue equal to 0xFFFFFFFFFFFFFFFF.

Notice that 0xFFFFFFFFFFFFFFFF is the same as 18,446,744,073,709,551,615 and this is the maximum value possible for an unsigned long long, depending on your processor architecture (as gineera said in its comment).

It's not so easy to understand all these things, but keep trying, it will be clearer after the end of this tutorial. At least, I hope it.

In the code part we will see that the number8 variable has a result of 255.
Why? Because 255 is the maximum value of an unsigned char or an uint8_t.
So if we put a value of 256, our result would be 0.
Indeed, after 255 we go back to 0.

For example if we added +1 for each

Answerd on:2019-06-20 Answerd By:rishabhshukla

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We're going to use a variable called testValue equal to 0xFFFFFFFFFFFFFFFF.

Notice that 0xFFFFFFFFFFFFFFFF is the same as 18,446,744,073,709,551,615 and this is the maximum value possible for an unsigned long long, depending on your processor architecture (as gineera said in its comment).

It's not so easy to understand all these things, but keep trying, it will be clearer after the end of this tutorial. At least, I hope it.

In the code part we will see that the number8 variable has a result of 255.
Why? Because 255 is the maximum value of an unsigned char or an uint8_t.
So if we put a value of 256, our result would be 0.
Indeed, after 255 we go back to 0.

For example if we added +1 for each

Answerd on:2019-06-20 Answerd By:rishabhshukla

Likes:
Be first to like this answer

Dislikes:
Be first to dislike this answer
Talk about this  Like  Dislike

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We're going to use a variable called testValue equal to 0xFFFFFFFFFFFFFFFF.

Notice that 0xFFFFFFFFFFFFFFFF is the same as 18,446,744,073,709,551,615 and this is the maximum value possible for an unsigned long long, depending on your processor architecture (as gineera said in its comment).

It's not so easy to understand all these things, but keep trying, it will be clearer after the end of this tutorial. At least, I hope it.

In the code part we will see that the number8 variable has a result of 255.
Why? Because 255 is the maximum value of an unsigned char or an uint8_t.
So if we put a value of 256, our result would be 0.
Indeed, after 255 we go back to 0.

For example if we added +1 for each

Answerd on:2019-06-20 Answerd By:rishabhshukla

Likes:
Be first to like this answer

Dislikes:
Be first to dislike this answer
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