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One kg of an ideal gas (gas constant R=287 J/kg.K) undergoes an irreversible process from state-1 (1 bar, 300 K) to state -2 (2 bar, 300 K). The change in specific entropy (s1-s2) of the gas (in J/kg.K) in the process is 1 Answer(Gate 2018 Mechanical engineering)An ideal gas undergoes a process from state 1 ( T1 = 300 K, 1 p = 100 kPa) to state 2 ( T2 = 600 K, 2 p = 500 kPa). The specific heats of the ideal gas are : cp = 1 kJ/kg-K and cv = 0.7 kJ/kg-K. The change in specific entropy of the ideal gas from state 1 to state 2 (in kJ/kg-K) is ___________0 AnswerFor an ideal gas with constant properties undergoing a quasi-static process, which one of the following represents the change of entropy (s) from state 1 to 2? (Gate 2018 Mechanical engineering)0 AnswerA certain amount of an ideal gas is initially at a pressure P1 and temperature T1. First, it undergoes a constant pressure process 1-2 such that T2 = 3T1/4. Then, it undergoes a constant volume process 2-3 such that T3 = T1/2. The ratio of the final 1 AnswerOne kmol of an ideal gas (Cp = 21 kJ/kmol.K) undergoes a constant pressure process from 300 K to 500 K. The molar entropy of the gas at 300 K is 150 kJ/kmol.K. The molar entropy (in kJ/kmol.K) at 500 K (up to 1 decimal place) is ________.0 AnswerO ne kg of air (that can be considered a calorically perfect gas with characteristic gas constant R = 287 J/kg-K and specific heat ratio 1.4 ) undergoes a constant-volume process from an initial static pressure of 1 bar to a final static pressure of 4 bar. The increase in entropy (in J/kg-K) of air is ______0 AnswerConsider the following statements for an ideal gas undergoing a reversible non-flow process: P. If the process is adiabatic, the change in enthalpy of the gas is necessarily zero. Q. If the process is adiabatic, the change in entropy of the gas is necessarily zero. R. If the process is isothermal, the change in enthalpy of the gas is necessarily zero. S. If the process is isothermal, the change in entropy of the gas is necessarily zero1 AnswerAdiabatic work of 200 kJ is done on ideal gas of mass m = 1 kg (Cv=1000 j/kgk ), which is stored in a rigid container at a pressure of 100 kPa and temperature 300 K.1 AnswerConsider a rigid, perfectly insulated, container partitioned into two unequal parts by a thin membrane (see figure). One part contains one mole of an ideal gas at pressure Pi and temperature Ti while the other part is evacuated. The membrane ruptures, the gas fills the entire volume and the equilibrium pressure is Pf = Pi⁄4. If Cp (molar specific heat capacity at constant pressure), Cv (molar specific heat capacity at constant volume) and R (universal gas constant) have the same units as molar entropy, the change in molar entropy (Sf − Si) is0 AnswerThe elementary irreversible gas-phase reaction A → B + C is carried out adiabatically in an ideal CSTR (Continuous-Stirred Tank Reactor) operating at 10 atm. Pure A enters the CSTR at a flow rate of 10 mol/s and a temperature of 450 K. Assume A, B and C to be ideal gases. The specific heat capacity at constant pressure ( CPi ) and heat of formation 0 ( ) Hi , of component i (i = A, B, C), are:0 AnswerThe molar specific heat at constant volume of an ideal gas is equal to 2.5 times the universal gas constant (8.314 J/mol.K). When the temperature increases by 100k, the change in molar specific enthalpy is ___ J/mol.1 AnswerManagement is the process of getting things done. State the meaning of the term process used in this statement. -CBSE business studies 2016 class 111 AnswerAccording to first law of thermodynamics1 AnswerState the steps in the process of controlling -Business studies cbse 2017 class 121 AnswerState the steps in the controlling process - CBSE business studies 2016 class 111 AnswerIn an ideal gas turbine cycle, the expansion in a turbine is represented by (GATE-Aerospace-Engineering-2018)1 AnswerAir of mass 1 kg, initially at 300 K and 10 bar, is allowed to expand isothermally till it reaches a pressure of 1 bar. Assuming air as an ideal gas with gas constant of 0.287 kJ/kg.K, the change in entropy of air (in kJ/kg.K, round off to two decimal places) is____0 AnswerAccording to first law of thermodynamics0 AnswerA microcanonical ensemble consists of 12 atoms with each taking either energy 0 state, or energy 𝜖 state. Both states are non-degenerate. If the total energy of this ensemble is 4𝜖, its entropy will be ________ 𝑘𝐵 (up to one decimal place), where 𝑘𝐵 is the Boltzmann constant.1 AnswerA first-order irreversible liquid phase reaction A → B k = 0.1 min−1 is carried out under isothermal, steady state conditions in the following reactor arrangement comprising an ideal CSTR (Continuous-Stirred Tank Reactor) and two ideal PFRs (Plug Flow Reactors). From the information in the figure, the volume of the CSTR (in Liters) is ___________ (rounded off to the nearest integer).0 Answer
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