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Rahu-in-Tenth-House-->View question

Asked On2019-04-10 11:19:37 by:Rohit498

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The characteristic equation is

s7 + s6 + 7s5 + 14s4 + 31s3 + 73s2 + 25s + 200 = 0 

Auxiliary equation is A(s) = 8s4 + 48s2 + 200

Differentiating this w.r.t. s we get d /ds A (s ) = + 32s3 +96s

Total number of poles = 7 Two sign changes above auxiliary equation = 2 poles in RHS

Two sign changes below auxiliary equation implies that out of 4 symmetric roots about origin, two poles are in LHS and two poles are in RHS. Therefore 3 poles in LHS and 4 poles in RHS.

Answerd on:2019-06-20 Answerd By:Gaganpreet-Gandhi

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