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CE2028-GROUND-WATER-ENGINEERING-->View question

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An inclined cylindrical confined aquifer has coefficient of permeability of 40 m/day.
The horizontal distance between two vertical wells penetrating the aquifer is 800 m.
The water surface elevations in the wells are 50 m and 45 m above a common horizontal datum.
Solution: 0.25
𝑄 𝐴 = 𝐾(ℎ‚ − ℎ[) ∆𝐿
Where Q/A is the darcy flux.
Given, K = 40m/day ,
∆𝐿 = 800m ,
h2 = 50m
and h1 = 45m
Substituting in the Darcy’s equation
𝑄 𝐴 = 40(50 − 45) 800 =
0.25𝑚/𝑑𝑎𝑦
Hence , the absolute value of Darcy flux through the aquifer is 0.25 m/day.

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