A quarter wave plate introduces a path difference of 4 between the two components of polarization parallel and perpendicular to the optic axis An electromagnetic wave with 0 is incident normally on a quarter wave plate which has its optic axis making an angle 135 with the axis as shown

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CG-and-Visualisation-Lab10CSL67-Vtu-prg-8-->View question

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## A quarter wave plate introduces a path difference of π/4 between the two components of polarization parallel and perpendicular to the optic axis. An electromagnetic wave with πΈβ =(π₯Μ+π¦Μ) πΈ0 ππ(ππ§βππ‘) is incident normally on a quarter wave plate which has its optic axis making an angle 135Β° with the π₯-axis as shown.

The emergent electromagnetic wave would be
(C) linearly polarized with polarization as that of incident wave

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