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physics-2013-->View question

By:milan-ransingh

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## A Projectile is given an initial velocity of Ë† Ë† (i 2j) m/s, + where Ë† i is along the ground and Ë† j is along the vertical. If g = 10 m/s2 - physics 2013

the equation of its trajectory is :

(1) y = x âˆ’ 5x^2

(2) y = 2x âˆ’ 5x^2

(3) 4y = 2x âˆ’ 5x^2

(4) 4y = 2x âˆ’ 25x^2

By:milan-ransingh

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