A hyperbola passes through the point P212312 and has foci at 2 0 Then the tangent to this hyperbola at P also passes through the point JEE MAINS Mathematics 2017 The Eduladder is a community of students, teachers, and programmers just interested to make you pass any exams. So we solve previous year question papers for you.
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Asked by:Purnima

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Aparna-Dasgupta

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Equation of hyperbola is
(x^2/a^2)-(y^2/b^2) = 1
foci is (±2, 0) hence ae = 2, thus, a^2e^2 = 4
b2 = a2(e2 – 1)
a^2 + b^2 = 4 ...(1)
Hyperbola passes through 2^(1/2), 3^(1/2)
2/(a^2)-3/(b^2)=1...(2)
On solving (1) and (2)
a^2 = 8 (is rejected) and a^2 = 1 and b^2 = 3
(x^2)/1-(y^2)/3=1

Equation of tangent is (2^(1/2)x)/1-(3^(1/2)y)/3=1
Hence (2(2)^(1/2),3(3)^(1/2)) satisfy it.

Answerd By:leo

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