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class-5-math-->View question

By:milan-ransingh

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Boundary for A = 2(40+20) m = 260 m = 120 m

Gold Wire for A = 120 metres

Boundary for B = 2(80+10) m = 2 90 m = 180 m

Gold Wire for B = 180 metres

Boundary for C = 2(800+1) m = 2 801 m = 1602 m

Gold Wire for C = 1602 metres

Boundary for D = 2(8000+0.1) m = 2 8000.1 m = 16000.2 m

So he will get 16000.2 metres of gold wire.

(b) Yes, a rectangle with a still longer boundary can be made.

Boundary of a rectangle 1 cm wide and 80000 m long.

= 2(.01+80000) m = 2 * 80000.01 m = 160000.02 m

pankaj

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## So Anar also tried many different ways to make a boundary for 800 square metres of land. -class 5 math

(a) He made rectangles A, B, C of different sizes. Find out the length of the boundary of each. How much gold wire will he get for these rectangles?

(b) Can you make a rectangle with a still longer boundary? I made a rectangle 1 cm wide and 80000 m long. Imagine how long that boundary will be!! With that much gold wire I can become the king!

By:milan-ransingh

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## Answers

(a) Boundary of a rectangle = 2(Length + Breadth)Boundary for A = 2(40+20) m = 260 m = 120 m

Gold Wire for A = 120 metres

Boundary for B = 2(80+10) m = 2 90 m = 180 m

Gold Wire for B = 180 metres

Boundary for C = 2(800+1) m = 2 801 m = 1602 m

Gold Wire for C = 1602 metres

Boundary for D = 2(8000+0.1) m = 2 8000.1 m = 16000.2 m

So he will get 16000.2 metres of gold wire.

(b) Yes, a rectangle with a still longer boundary can be made.

Boundary of a rectangle 1 cm wide and 80000 m long.

= 2(.01+80000) m = 2 * 80000.01 m = 160000.02 m

pankaj

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