viewnotes/207/Design and Analysis of Algorithms Subject Code 10CSL47 Lab Manual PROGRAM 12

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Take a thick paper sheet of length 14 cm and width 9 cm. You can also use an old postcard. (a) What is its area? What is its perimeter? (b) Now cut strips of equal sizes out of it. (c) How long it your belt? (d) What is its Perimeter? (e) Whose belt is the longest in the class? - class 5 math

class 5 math chapter 11


By:milan-ransingh

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Answers

Ans. (a) We know that,
    Area of a rectangle = Length * Breadth
Area of a thick paper sheet = (Length * Breadth)
= (14*9) square cm = 126 square cm
Perimeter of a rectangular sheet
= 2(Length+ Breadth)
= 2(14 + 9) cm
= 2 * 23 cm = 46cm
 
(b)  Let us cut strips of equal sizes out of the given paper sheet of length 14 cm and width  9 cm.
 
(c) Strips having width 1 cm:
There will be 9 strips of width 1 cm and length 14 cm. Let us join these strips end to end using tape to make a belt.
Its length
= (14+14+14+14+14+14+14+14+14)
= 9 * 14 cm = 126 cm
It’s perimeter = 2(126+1) cm = 2  127 cm = 254 cm
 
(d)  Strips having length 1.5 cm:
There will be 6 strips of width 1.5 cm and length 14 cm. Let us join these strips end to end using tape to make a belt.
It’s length = (14+14+14+14+14+14) cm
= 6 * 14 cm = 84 cm
It’s perimeter = 2 (84 + 1.5) cm = 2*  85 – 5 cm = 171 cm
 
(e) Whose belt is the longest in the class?
Ans. (e) Strips having width 3 cm:
There will be 3 strips of width 3 cm and length 14 cm.
Let us join these strips end to end using tape to make a belt.
It’s length = (14+14+14) cm = 3 * 14 cm = 42 cm
It’s perimeter = 2(42+3) cm = 2 * 45 cm = 90 cm
Clearly, the belt with shortest width is the longest one. Thus, the belt having width 1 cm is the longest in the class. So, my belt is the longest.

pankaj

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