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CBSE-Class-6-Mathematics-NCERT-->View question

## Present age of father is 42 years and that of his son is 14 years. Find the ratio of-Mathematics-cbse-std 6th-Ratio and Proportion

##### (a) Present age of father to the present age of son.(b) Age of the father to the age of son, when son was 12 years old.(c) Age of father after 10 years to the age of son after 10 years.(d) Age of father to the age of son when father was 30 years old.

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Abhijeet

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Present age of father = 42 years
Present age of his son = 14 years
a) Age of father: age of son
= 42: 14
=42/14
=3/1
= 3: 1
b) When the son was 12 = (14 – 2) years old,
the father would have been 40 = (42 – 2) years old.
Age of father: Age of son = 40: 12 = 10: 3
c) Age of father after 10 years = Present age + 10 = 42 + 10 = 52 years
Age of son after 10 years = 14 + 10 = 24 years
Age of father: Age of son = 52: 24 = 13: 6

d) When was the father 30 years old?
Since, 42 – 30 = 12, we know that 12 years back, the father was 30 years old.
So Age of son 12 years back was = present age – 12 = 14 − 2 = 2 𝑦𝑒𝑎𝑟
Ratio of father: Age of son = 30: 2 = 15: 1

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