Construct a triangle ABC with side BC 7 cm B 45 A 105 Then construct another triangle whose sides are 3 4 times the corresponding sides of the triangle ABC Mathematics CBSE class 10 2017
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Construct a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then construct another triangle whose sides are 3 / 4 times the corresponding sides of the triangle ABC. Mathematics CBSE class 10 2017

Construct a triangle ABC with side BC = 7 cm, ∠B = 45°, ∠A = 105°. Then construct another triangle whose sides are 3 / 4 times the corresponding sides of the triangle ABC.


By:tarun101

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Sum of all side of triangle = 180°
∴ ∠A  + ∠B  + ∠C  = 180°
∠C = 180° - 150° = 30°
Steps of Construction:
Step I: BC = 7 cm is drawn.
Step II: At B, a ray is drawn making an angle of  45° with BC. 

Justification:

∠B = 45° (Common)
∠C = ∠C'
ΔAB'C' ~  ΔABC by AA similarity condition.
∴ BC/BC' = AB/A'B' = AC/A'C'
also,
BC/BC' = BB3/BB4 = 34
⇒ AB = 4/3 AB', BC = 4/3 BC' and AC = 4/3 A'C' 

prajwalamv

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