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If n is odd then Median (M) = value of ((n + 1)/2)th item term. Try sorting the array first. Then after it's sorted, if the array has an even amount of elements the mean of the middle two is the median, if it has a odd number, the middle element is the median

// Median and mean

#include<stdio.h>

#include<conio.h>

void main()

{

int x[100],n,i;

float mean(int,int[]);

float median(int,int[]);

clrscr();

scanf("%d",&n);

for(i=0;i<n;i++)

scanf("%d",&x[i]);

printf("mean=%f\n",mean(n,x));

printf("median=%f\n",median(n,x));

getch();

}

float mean(int m, int a[]) {

int sum=0, i;

for(i=0; i<m; i++)

sum+=a[i];

return((float)sum/m);

}

float median(int n, int x[]) {

float temp;

int i, j;

// the following two loops sort the array x in ascending order

for(i=0; i<n-1; i++) {

for(j=i+1; j<n; j++) {

if(x[j] < x[i]) {

// swap elements

temp = x[i];

x[i] = x[j];

x[j] = temp;

}

}

}

if(n%2==0) {

// if there is an even number of elements, return mean of the two elements in the middle

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## How to calculate median of an array? Use any programming language you would like to use.

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## Answers

If n is odd then Median (M) = value of ((n + 1)/2)th item term. Try sorting the array first. Then after it's sorted, if the array has an even amount of elements the mean of the middle two is the median, if it has a odd number, the middle element is the medianprajwalamv

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