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Database-Management-Systems---10CS54-VTU-notes-->View question


) Explain lossless join property Database Management Systems - 10CS54 VTU notes (MAY/JULY 2013/Jan 2016)

EXplain with example?

By:anonymousguy7799

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Lossless (Non-additive) Join Property of a Decomposition: Definition: Lossless join property: a decomposition D = {R1, R2, ..., Rm} of R has the lossless (nonadditive) join property with respect to the set of dependencies F on R if, for every relation state r of R that satisfies F, the following holds, where * is the natural join of all the relations in D: * (π R1(r), ..., πRm(r)) = r 

Algorithm 11.1: Testing for Lossless Join Property Input: A universal relation R, a decomposition D = {R1, R2, ..., Rm} of R, and a set F of functional dependencies. 1. Create an initial matrix S with one row i for each relation Ri in D, and one column j for each attribute Aj in R. 2. Set S(i,j):=bij for all matrix entries. (* each bij is a distinct symbol associated with indices (i,j)*). 3. For each row i representing relation schema Ri {for each column j representing attribute Aj {if (relation Ri includes attribute Aj) then set S(i,j):= aj;};}; (* each aj is a distinct symbol associated with index (j) *) Algorithm 11.1: Testing for Lossless Join Property
4. Repeat the following loop until a complete loop execution results in no changes to S {for each functional dependency X Y in F {for all rows in S which have the same symbols in the columns corresponding to attributes in X {make the symbols in each column that correspond to an attribute in Y be the same in all these rows as follows: If any of the rows has an “a” symbol for the column, set the other rows to that same “a” symbol in the column. If no “a” symbol exists for the attribute in any of the rows, choose one of the “b” symbols that appear in one of the rows for the attribute and set the other rows to that same “b” symbol in the column ;}; }; };
 5. If a row is made up entirely of “a” symbols, then the decomposition has the lossless join property; otherwise it does not. Lossless (nonadditive) join test for n-ary decompositions. (a) Case 1: Decomposition of EMP_PROJ into EMP_PROJ1 and EMP_LOCS fails test. (b) A decomposition of EMP_PROJ that has the lossless join property 


Nikhil-bharadwaj

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