See Our team

Wondering how we keep quality?

Got unsolved questions?

Ask Questions

Engineering
GATE
CBSE
NCERT
Psychology
English
Computer
Constitution
Astrology
Yoga
Economics
Physics
Biology
Electronics
Microprocessor
Career
Interview
Anatomy
Botany

## A sonometer wire of length 1.5 m is made of steel. The tension in it produce an elastic strain of 1%. What is the fundamental frequency of steel if density and elasticity of steel are 7.7 Ã— 103 kg / m3 and 2.2 Ã— 1011 N/m2 respectively ? - physics 2013

(1) 188.5 Hz

(2) 178.2 Hz

(3) 200.5 Hz

(4) 770 Hz

By:milan-ransingh

Taged users:

Likes:

Be first to like this question

Dislikes:

Be first to dislike this question

Talk about thisDelete|Like|Dislike|

## Answers

Transverse waves on a Sonometer wire/bridge . Young's modulus Y = Stress / Strain = 2.2 * 10^11 N/mÂ² Stress = Tension / Cross section area = T / A Strain = 1 % = 0.01 2.2 * 10^11 = (T / A ) / 0.01 = T / (0.01 A) T = 2.2 * 10^9 * A Newtons L = 1.5 meter Volume density d = 7.7 * 10Â³ kg/mÂ³ Linear density Î¼ = volume density * Area = d * A = 7.7 * 10Â³ * A kg /meter velocity of transverse wave on the Sonometer wire = âˆš(T/Î¼) v = âˆš(2.2*10^9 / 7.7*10Â³) m/sec = 534.52 m/sec Fundamental note has a wavelength = Î» = 2 * L = 3 meters. As the given wire vibrates with one loop. Nodes at both ends and anti-node at the center. So half of the wavelength is equal to the length of the wire.

So frequency = v / Î» = 178.17 Hz

**(2) 178.2 Hz**

_{}

^{}

satyashiromani

Likes:

Be first to like this answer

Dislikes:

Be first to dislike this answer

Talk about this|Once you have earned teacher badge you can edit this questionDelete|Like|Dislike|

------------------------------------

#### Can you help us to add better answer here? Please see this

Loading...

## Use Me ?