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Moon-in-eleventh-House-->View question

By:Purnima

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## A man X has 7 friends, 4 of them are ladies and 3 are men. His wife Y also has 7 friends, 3 of them are ladies and 4 are men. Assume X and Y have no common friends. Then the total number of ways in which X and Y together can throw a party inviting 3 ladies and 3 men, so that 3 friends of each of X and Y are in this party, is :-JEE MAINS-Mathematics-2017

(1) 484 (2) 485 (3) 468 (4) 469It is related to jee mains 2017.

By:Purnima

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## Answers

Total number of ways

4C0 · 3C3 · 3C3 · 4C0 + 4C1 · 3C2 · 3C2 · 4C1

+ 4C2 · 3C1 · 3C1 · 4C2 + 4C3 · 3C0 · 3C0 · 4C3

= 485

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